Question: 83) Imagine A Beaker Divided Down The Center By A Rigid Membrane That Is Freely Permeable To Water But Impermeable To Glucose. Side 1 Contains A 10 Percent Glucose Solution And Side 2 Contains A 5 Percent Glucose Solution. At Equilibrium, What Will Be The Situation? A) Water Will Continue To Move From Side I To Side 2. B) Water Will Continue To Move …

83) Imagine a beaker divided down the center by a rigid membrane that is freely permeable to water but impermeable to glucose. Side 1 contains a 10 percent glucose solution and side 2 contains a 5 percent glucose solution. At equilibrium, what will be the situation? A) Water will continue to move from side I to side 2. B) Water will continue to move from side 2 to side 1. C) The volume of liquid will be greater in side 1. D) The volume of liquid will be greater in side 2. E) The volume of liquid remains equal on both sides. 84) Which solution will cause the hemolysis of red blood cells when red blood cells are placed in this solution? A) isotonic B) hypertonic C) hypotonic D) merotonis E) homotonic